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Module 2 exercise

A
Anjali C Post on 08/10/2019

For the question below, the answer given does not print the highest value which is 311. How to achieve this?

 

Print how many times has a number repeated in following array
int x[] ={1,3,4,5,6,3,2,4,6,7,9,4,12,3,4,6,8,9,7,6,43,2,4,7,7,5,2,1,3,4,6,311,1};

Your output should look like
1- 3 times
2 - 2 times
...

The logic should work even if we change the array.

S

Instructor

Support Team Reply on 09/10/2019

Thanks for your report.

The question has been updated with the new code.

You can find the solution below.

public class Ques10 {
	public static void main(String[] args) {
		int x[] = { 1, 3, 4, 5, 6, 3, 2, 4, 6, 7, 9, 4, 12, 3, 4, 6, 8, 9, 7, 6, 43, 2, 4, 7, 7, 5, 2, 1, 3, 4, 6, 311,1 };
//		arrange in ascending order
		for (int i = 0; i < x.length - 1; i++) {
			for (int j = i; j < x.length; j++) {
				if (x[i] > x[j]) {
					int temp = x[i];
					x[i] = x[j];
					x[j] = temp;
				}
			}
		}
//		print ascending order array
		for (int i = 0; i < x.length; i++) {
			System.out.println("Array in ascending order -> " + x[i]);
		}
		int c = 1;
		for (int i = 0; i <= x.length - 1; i++) {
			int currentValue = x[i];
			int nextValue = 0;
			try {
				nextValue = x[i + 1];				
			} catch (Exception e) {
			}
			if (currentValue != nextValue) {
				System.out.println(x[i] + " repeated " + c + " times ");
				c = 1;
			} else {
				c++;
			}
		}
	}
}

A
Anjali C Reply on 09/10/2019

Thanks!